Question

log(a+b/2)=1/2(log a+log b) show 1/2(a+b)=√ab​

Answer 1

log(a+b/2)=1/2(log a+log b)

log[(a+b)/2]=1/2[log(ab)]

log[(a+b)/2]=log[(ab)^(1/2)]

[(a+b)/2]=√ab

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