Question

Log b base a + log c base a=0

Answer 1

Answer:

b=1/c

Step-by-step explanation:

log(a) b + log(a) c = 0

log(a) bc = 0

bc = a⁰

bc = 1

b = 1/c

Answer 2

Solution:

$log_{a} b + log_{a} c = 0$

$\implies log_{a} (bc) = log_{a}1$

Remove the logarithm both sides , we get

$ bc = 1 $

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