Question

log (log^3)-log (log x)=log3

Answer 1

$log( log^{3} ) - log( logx ) \\ = log( log^3 - logx) \\ = log(3)$

Answer 2

Answer:

$x = {3}^{ \dfrac{1}{3} }$

Step-by-step explanation:

$\\\tt log( log3) - log( logx) = log3 \\ \\\tt \implies log( \dfrac{ log3 }{ logx } ) = log(3) \\\tt \implies \dfrac{ log3}{ logx } = 3 \\\tt \implies log(3) = 3 log(x) \\\tt \implies3 = {x}^{3} \\ \implies \: x = {3}^{ \dfrac{1}{3} }$