Question

log (mnp) = log m + log n + log p

Answer 1

log (mnp)=log (mn)+log p
log (mnp)=log m+log n+ log p

Answer 2

I don't really think that its possible but wait an example may be
$log(8) + log(4) + log(4) \\ = log(4 \times 4\times8 ) \\ \\ log(8) + log(4) + log(4) \\ = log(128) \\ \\ thus \: it \: is \: \\ possible \: when \: m \: n \:and \\ \: p \: are \: of \: same \: integers \\ \:as \: in \: this \: case \: is \: 2.$

log(MNP)=log(mn)+log(p)
log(MNP)=log(m)+ log(n)+log(p)