Question

log rootx base x value​

Answer 1

Answer:

2

Step-by-step explanation:

X's root can be written as x^(1/2)

Using this in the equation:

logx^(1/2) x^1

2 * logx x (Using the identity of logi.e. loga^m n^l =l/m*log a n

log x x=1

1*2=2.

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Answer 2

$\log_x (\sqrt x)=\frac{1}{2}$

Step-by-step explanation:

Given : Expression $\log_x (\sqrt x)$

To find : The value of the expression ?

Solution :

Write the expression as,

$\log_x (\sqrt x)=\log_x (x)^{\frac{1}{2}}$

Using logarithmic property,  $\log a^x=x\log a$

$\log_x (\sqrt x)=\frac{1}{2}\log_x (x)$

Again using logarithmic property, $\log_a a=1$

$\log_x (\sqrt x)=\frac{1}{2}(1)$

$\log_x (\sqrt x)=\frac{1}{2}$

Therefore, $\log_x (\sqrt x)=\frac{1}{2}$

#Learn more

2^n= 512 find the value of n in each of the following​

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