Question

log sin inverse x differtiate​

Answer 1

Answer:

pls see the attachment

Answer 2

Answer:

d/dx (log sin inverse x)

1/ sin inverse x [d/dx(sin inverse x)]

1/ sin inverse x [1/ √(1- x^2)]

hope this helps

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Step-by-step explanation:

rule

d/dx(log x) = 1/x

d/dx( sin inverse x) = 1/ √(1-x^2)