Log tan1*log tan2.........................*logtan89=0
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Answered by
13
=logtan1+logtan2+logtan3+...........+logtan89
=log{tan1×tan2×...................×tan89}
=log{tan1×tan2×......×tan45×.........×tan89}
=log{tan1×tan2×....×1×...........tan(90-2)×tan(90-1)}
=log{tan1×tan2×...×1×...........cot2×cot1}
=log{1}
=log1
=log10^0
=0×log10
=0×1
=0
and,
=logtan1×logtan2×.........×logtan89
=logtan1×logtan2×.......×logtan45×......×logtan89
=logtan1×logtan2×........log1×........×logtan89
=logtan1×logtan2×........log10^0×......×logtan89
=logtan1×logtan2×........×0×........logtan89
=0
=log{tan1×tan2×...................×tan89}
=log{tan1×tan2×......×tan45×.........×tan89}
=log{tan1×tan2×....×1×...........tan(90-2)×tan(90-1)}
=log{tan1×tan2×...×1×...........cot2×cot1}
=log{1}
=log1
=log10^0
=0×log10
=0×1
=0
and,
=logtan1×logtan2×.........×logtan89
=logtan1×logtan2×.......×logtan45×......×logtan89
=logtan1×logtan2×........log1×........×logtan89
=logtan1×logtan2×........log10^0×......×logtan89
=logtan1×logtan2×........×0×........logtan89
=0
Anonymous:
yess we can follow log summation rule
but here in question product is given
thanks
again u did wrong
u changed question
here question is given as product logtan1.ligtan2.logtan3..............but u changed as logtan1 + logtan2 .....+ logtan89 ....its wrong..
now both are there
it is more helpful to understand differences
so where i got confused other wont get confused there
oh
Answered by
9
hey friend .
given that ;-
logtan1.logtan2.logtan3..........logtan89
so we can write as..
logtan1.logtab2.....logtan45.....logtan89
we know that tan45 = 1
so logtan45 = log1 =0
=) logtan1× logtan2 × logtan3 × 0 × ...........logtan89 = 0
______________________________
hope it will help u
given that ;-
logtan1.logtan2.logtan3..........logtan89
so we can write as..
logtan1.logtab2.....logtan45.....logtan89
we know that tan45 = 1
so logtan45 = log1 =0
=) logtan1× logtan2 × logtan3 × 0 × ...........logtan89 = 0
______________________________
hope it will help u
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