Question

log: ((x - 1)(2x - 1)) = 0​

Answer 1

Answer:

Step-by-step explanation:

log(2x+1)=1-log(x-1)

log(2x+1)+log(x-1) = 1

log[(2x+1)(x-1)] = 1

2x^2-x-1 = 10

2x^2-x-11 = 0

Use the quadratic formula

x = 2.608  and -2.108 (discard)

x = 2.608

hope it helps

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