Question

log (x+1) + log (x-1)= log 11 + 2log3

Answer 1

I hope it helps.....

Answer 2

$log(x + 1) + log(x - 1) = log(11) + 2log(3) \\ or. \: log(x + 1) + log(x - 1) = log(11) + log( {3}^{ {2} } ) \\ or. \: log((x + 1)(x - 1)) = log(11 \times {3}^{2} ) \\ or. \: (x + 1)(x - 1) = 11 \times 9 \\ or. \: {x }^{2} - 1 = 99 \\ or. \: {x }^{2} = 100 \\ or.x = \sqrt{100 } \\ so..x = + 10..or..-10$
Hope x= ±10 is ur required answer.