Question

log x + 1/log x = 2
Find x

Answer 1

Answer:

x = 10^1 = 10

Step-by-step explanation:

log x + 1 ÷ 1ogx = 2

let consider ;

log x = y .........(1)

So the equation become

y + (1/y) = 2

y^2 + 1 = 2y

y^2 - 2y + 1 = 0

y^2 - y - y + 1 = 0

y(y - 1) -1(y - 1) = 0

y - 1 = 0

y = 1 ......(2)

As we consider early that

y = log x

from equation 1 & 2

log x = 1

we know that common base of log is 10

So, x = 10^1 = 10

if your confuse in any of the step let me know