Question

log(x^2-1) - log(x+1)= -log9​

Answer 1

Answer:

10/9

Step-by-step explanation:

$log( {x}^{2} - 1 ) - log(x + 1) = - log(9) \\ \\ log((x - 1)(x + 1) \div (x + 1)) = log( \frac{1}{9} ) \\ \\ log(x - 1) = log( \frac{1}{9} ) \\ \\ x - 1 = \frac{1}{9} \\ \\ x = \frac{10}{9}$