Question

log (x^2 _2x) = 1 find x​

Answer 1

Answer:

1 ± √11

Step-by-step explanation:

log (x^2 _2x) = 1

log (x² - 2x) = 1

x² - 2x = 10

x² - 2x - 10 = 0

x = (2 ±√44)/2 = 1 ± √11