Question

(log x) 3 -6(log x) 2 +11(log x)-6 <=0 FIND VALUE OF X????

Answer 1

let  log x = m,  hence  expression  becomes

m3 - 6 m2  + 11m - 6 = 0,  m - 1  is  a  factor, so

m3 - m2 - 5m2 + 5m + 6m - 6 = 0  or

( m - 1 ) ( m2 - 5m + 6 ) = 0  or ( m - 1) ( m - 2 ) ( m - 3 ) = 0

when m = 1, x = 10.  when m = 2, x = 100,  when  m = 3, x = 1000