log(x+3)+log(x-3)=log16 Solve for x
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Log(a) + log(b) = log(ab)
log(x+3) + log(x-3) = log[(x+3)*(x-3)] = log( - )
 - 9 =16
x =5
log(x+3) + log(x-3) = log[(x+3)*(x-3)] = log( - )
 - 9 =16
x =5
Answered by
1
loga +log=log(ab)
log(x+3)+log(x-3)=log16
log[(x+3)(x-3)]=log 16
log(x^2-9)=log 16
comparing both sides.
x^2-9=16
x^2=16+9=25
x=√25=5
Hence, x=5
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log(x+3)+log(x-3)=log16
log[(x+3)(x-3)]=log 16
log(x^2-9)=log 16
comparing both sides.
x^2-9=16
x^2=16+9=25
x=√25=5
Hence, x=5
please mark me as brainliest and follow me
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