log(x+3) +log(x-3) =log27
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We have given log function both sides so,we apply logorithm identity here to solve this type of Questions
=>log(x+3)+log(x-3)=log27
On the left side there is variable and on the other side there is constant inside log.So, it's difficult to solve without using any logorithm property.
We know that : logm + logn= logmn
The function on the left side is in the form of logm+logn
So, log (x+3)+log(x-3)= log(x+3)(x-3)
=>log(x+3)(x-3)= log27
Here,we see that log on both sides so,log will be cancelled
=>(x+3)(x-3)= 27
Here ,(x+3)(x-3) is the form of identity (a+b)(a-b)
Identity used here :
(a+b)(a-b)=a²-b²
=>x²-3²=27
=>x²-9=27
=>x²=27+9=36
=>x=√36
=>x=6
Extra information=>
Some other logorithm properties:
- logm-logn= logm÷long
- value of log1=0
- logbase e will be considered as 1
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