Question

The percentage of increase in the area of a rectangle if sides are doubled

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Answer 1

Answer:

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Answer 2

300%

Let the length of the rectangle be L cm and breadth be B cm.

Hence, area of the rectangle = (L x B) sq.cm. = LB sq.cm.

Now, the sides are doubled.

Therefore the area = (2L x 2B) sq.cm. = 4LB sq.cm.

Therefore, increase in the area of the rectangle = {(4LB - LB)/LB x 100}% = (3LB / LB x 100)% = 300%.

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