Question

Log(x+3)+log(x-5)=2log3

Answer 1

Answer:

log(x+3) + log(x-5) = 2log3

log(x+3)(x-5) = log(3)^2

log(x^2 - 2x - 15) = log9

x^2 - 2x - 15 = 9

x^2 - 2x - 24 = 0

x^2 - 6x + 4x - 24 = 0

x(x - 6) +4(x - 6) = 0

(x + 4)(x - 6) = 0

Hence value of x will be - 4 and 6

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