Question

log ( x+4) - log 7 = 3 log 2 - log (x+5)........solve x

Answer 1

We know that lox(X)-log(y)=log(x÷y) and xlog(y)=log(y^x) therefore the above problem can be solved as-

Log((X+4)/7)=log(2^3÷x+5)

(X+4)÷7=8÷(X+5)

(X+4)(X+5)=56

X²+5x+4x+20=56

X²+9x-36=0

X²+3x-12x-36=0

X(X+3)-12(X+3)=0

X=12 or X=-3

Answer 2

i hope it will help you