Question

log (x+5)+log(x-5) =4 log2+2 log 3

Answer 1

Using the property that
1) log A + log B = log A.B
2) a log B = log B^a

Answer 2

Answer:

13

Step-by-step explanation:

• log(a)+log(b)=log(ab)

1. So log[(x+5)(x-5)]=>>>>>(a+b)(a-b)=a^2-b^2

• log(x^2-5^2)=>>>log(x^2-25) keep it aside lhs cleared...

And now rhs,

• Log m^n=n log m and vice versa

So 4log2 becomes log 2^4 and 2log3 becomes log 3^2

As already given formula,

log a+ log b=log(ab)

• log{(2^4)(3^2)}=log(16*9)=>log(144)
• Now equating lhs and rhs,
• log(x^2-25)=log{144}
• log cancelled on both sides
• SO x^2-25=144
• x^2=144+25=169
• 13 square is 169 and so x is 13