Question

Log(x+y)÷log2=log(x-y)÷log3=log64÷log0.125 find the value of x and y

Answer 1

log (x+y-2)=log (x-y-3)=log (64-0.125)
log (x+y-2)=log (63.775)
x+y-2=63.775
x+y=65.775 eq 1st
log (x-y-3)=log63.775
x-y=66.775 eq 2nd
eq 1st +2nd
2x=132.55
x=66.275
putting the value of x in eq 1st then
66.275+y=65.775
y=-.775