log(x²+4x+4) to the base (x+2)=0
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log₍ₓ₊₂₎⁽ˣ²⁺⁴ˣ⁺⁴⁾ = 0
x² +4x + 4 =1
x² +4x +3 = 0
x = -1 and -2
for log to be defined
x²+4x+4 > 0
(x +2)² > 0 for all x∈R
again,
x+2 ≠0 and x+2 > 0 , x > -2
hence x = -1 is the answer
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