Solve (x+1)log(x+1) = 100(x+1) ( base is 10)
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8
(x+1)^log(x+1) = 100(x +1)
take log both sides log
log(x+1).log(x+1) = 2 + log(x +1)
{log(x+1)}² = 2 + log(x+1)
let log(x+1) = P
p² - P -2 = 0
P² -2P +P -2 = 0
P = -1 and 2
log(x +1) = -1 and 2
(x +1) = 1/10 and 100
x = -9/10 and 99
take log both sides log
log(x+1).log(x+1) = 2 + log(x +1)
{log(x+1)}² = 2 + log(x+1)
let log(x+1) = P
p² - P -2 = 0
P² -2P +P -2 = 0
P = -1 and 2
log(x +1) = -1 and 2
(x +1) = 1/10 and 100
x = -9/10 and 99
Answered by
9
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