CBSE BOARD XII, asked by ishanpriyadarshi, 1 year ago

Solve (x+1)log(x+1) = 100(x+1) ( base is 10)

Answers

Answered by abhi178
8
(x+1)^log(x+1) = 100(x +1)
        take log both sides log 
log(x+1).log(x+1) = 2 + log(x +1) 
{log(x+1)}
² = 2 + log(x+1) 
           let log(x+1) = P
p
² - P -2 = 0
P² -2P +P -2 = 0
P = -1 and 2 
log(x +1) = -1 and 2 
(x +1) = 1/10 and 100
x = -9/10 and 99


   
Answered by QHM
9

The answer is provided in the attachment.

Attachments:
Similar questions