(log x² – log x) . log 1/x + (log x)² = 0
Answers
Answered by
2
Step-by-step explanation:
(2 log x - log x) *(log 1 - log x) +2 logx
log x *(- logx) + 2log x (log1=0)
(-log x) ^2+ 2log x
-2log x + 2 log x =0
Answered by
2
Answer:
(log x² – log x) . log 1/x + (log x)² = 0
Step-by-step explanation:
(log x² – log x) . log 1/x + (log x)²
Hence proved.
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