Math, asked by patraavijit637, 2 months ago

(log x² – log x) . log 1/x + (log x)² = 0​

Answers

Answered by chakrapanisharma001
2

Step-by-step explanation:

(2 log x - log x) *(log 1 - log x) +2 logx

log x *(- logx) + 2log x (log1=0)

(-log x) ^2+ 2log x

-2log x + 2 log x =0

Answered by HariesRam
2

Answer:

(log x² – log x) . log 1/x + (log x)² = 0

Step-by-step explanation:

(log x² – log x) . log 1/x + (log x)²

 =( 2 log(x)  -  log(x) ).( log(1)  -  log(x) ) +  {( log(x) )}^{2}

 = ( log(x) ).(0 -  log(x) ) +  {( log(x)) }^{2}

 =  log(x) .( -  log(x) ) +  {( log(x)) }^{2}

 =  -  {( log(x) )}^{2}  +  {( log(x) )}^{2}

 = 0

Hence proved.

Similar questions