Question

log0.3÷log0.8
please tell how to solve
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Answer 1

Answer:

logb(x) = y

logb(x) = yx = logb(bx)

logb(x) = yx = logb(bx)logb(x) = y is equivalent to x = by

logb(x) = yx = logb(bx)logb(x) = y is equivalent to x = byb: log base number, b>0 and b≠1

logb(x) = yx = logb(bx)logb(x) = y is equivalent to x = byb: log base number, b>0 and b≠1x: is real number, x>0