log10(xy)=2 and log10(x/y)+2log10^2=2
find x and y
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Answered by
0
Step-by-step explanation:
log
10
x+log
10
y≥2
⇒log
10
xy≥2,[∵loga+logb=log(ab)]
⇒xy≥10
2
=100 ...(1)
Here also we have, x>0 & y>0 since x&y are under log
And we know, A.M.≥G.M
∴
2
x+y
≥
xy
⇒
2
x+y
≥
100
=10 ....{ From 1}
⇒x+y≥20
Answered by
0
Step-by-step explanation:
thank you this is with explanation
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