Math, asked by sparsh7113, 9 months ago

Q1. On what principal, S.I of 5 years at the rate of 6 % if Rs. 90?
(a) Rs. 450 (b) Rs. 400 (c) Rs. 250 (d) Rs. 300
Q2. Find the Compound Interest on Rs. 5000 at the rate of 10 % per annum for 2 years.
(a) 1010 (b) 4000 (c) 1000 (d) 2000
Q3. In selling a plot of land for Rs. 61200, a profit of 20 % is made. The cost price of the plot is
(a) Rs. 51000 (b) Rs. 50000 (c) Rs. 49000 (d) 52000
Q4. A shopkeeper purchased 2 refrigerators for Rs. 9800 and Rs. 8200 respectively. He sold them for
Rs. 16920. Find loss %
(a) 2 % (b) 4 % (c) 5 % (d) 6 %
Q5. In a school out of 340 students, 55 % students are of Science. The remaining Students are of
Commerce. Find the number of students of Commerce.
(a) 135 (b) 153 (c) 315 (d) 140
Q6. In a mixture the amount of Zinc is 45 %. Find the amount of zinc in 400g mixture.
(a) 60 g (b) 120 g (c) 180 g (d) 200 g
Q7. A sofa set was bought for Rs. 10000. Its value depreciated at the rate of 10 % per annum. Find its
value after one year.
(a) Rs. 11000 (b) Rs. 9000 (c) Rs. 10000 (d) Rs. 1000
Q8. A bag is available for Rs. 90. The shopkeeper allows 10 % discount on marked price. What is the
marked price of bag?
(a) Rs. 100 (b) Rs. 90 (c) Rs. 110 (d) Rs. 10
Q9. The fraction 2/5 converted to percentage is
(a) 20 % (b) 30 % (c) 40 % (d) 50 %
Q10. Ramesh purchased a sewing machine for Rs. 2000. He sold it at a loss of 40 %. Find the selling
price?
(a) Rs. 1200 (b) Rs. 400 (c) Rs. 800 (d) Rs. 2800

Answers

Answered by sbmahendrakumar
1

Answer:

Q1. 300 ( d )

Q2. 4000 ( b )

Q3. 51000 ( a )

Step-by-step explanation:

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Answered by gunjanbaidyasl
0

Answer:

(1) The correct option is (d) 300/-

(2) The correct answer is 1050/-.

(3) The correct option is (a) Rs 51000.

(4) The correct option is (d) 6%.

(5) The correct option is (b) 153.

(6) The correct option is (c) 180g.

(7) The correct option is (b) Rs. 9000.

(8) The correct option is (a) Rs 100.

(9) The correct option is (c) 40%.

(10) The correct option is (a) Rs 1200.

Step-by-step explanation:

(1) Given, Simple Interest = Rs 90.

                Rate = 6 %

                Time = 5 years

   We know, Simple Interest = \frac{Principal  X  Rate X  Time}{100} \\

                       = 90 =  \frac{PrincipalX6X5}{100}

                       = Principal = \frac{90 X100}{6X5}  = Rs 300/-

So, The Principal Amount is Rs 300/-

(2) Given, Principal P = Rs 5000/-

                Rate R = 10%

                Time T = 2years

     We know, Amount = P (1 + \frac{R}{100} )^{T}

                                     = 5000 (1+ \frac{10}{100} ) ^{2}

                                     = 5000 X \frac{11}{10} X \frac{11}{10} = Rs. 6050/-

                       Compound interest = Amount - Principal

                                                         = 6050 - 5000

                                                         = 1050/-

So the compound interest is 1050/-

(3)  Given, selling price = 61200/-

                  Profit = 20%

  Let cost price be x.

  According to question, x+ 20% of x = 61200/-

                                         x + 0.2x = 61200

                                         1.2x = 61200

                                          x = \frac{61200}{1.2}

                                          x = 51000/-

So, the cost price of the plot is (A) 51000/-

(4) Given cost price of two refrigerators = 9800 +  8200 = 18000/-

                Selling price = 16920/-

                 Loss = C.P. - S.P. = 18000 - 16920 = 1080

     Loss  Percentage = \frac{LOSS}{COST PRICE} X 100% = \frac{1080}{18000} X 100% = \frac{1080}{18000} X 100% = 6%

    Therefore, loss % is 6%.

(5) Percentage of students in commerce stream

    = 100 - Percentage of science students

   = 100 - 55%

   = 45%(of total students)

   Number of Commerce students = Total students x 45%

                                                         = 340 x 45% = 153(b)

  Number of students in Commerce = 153 (b).

(6) Amount of Zinc in a mixture = 45%.

    Amount of Zinc in a 400g mixture = 400 x 45% = 180g(c).

(7) Original Price of sofa set = 10000

   Depreciation rate = 10%

   Value after 1 year = 10000 - 10% of 10000

                                 = 10000 - 1000 = 9,000(b)

  The value of the sofa set after one year will be 9,000/-

(8) Given bag is available for Rs 90/-

   Let marked price of bag be x.

   x - 10% of x = 90

   x - 0.1x = 90

   0.9x = 90

    x = \frac{90}{0.9}  = 100 Rs.

  Thus, the marked price of the bag will be Rs. 100. (a)

(9) The Fraction 2/5 converted to percentage is \frac{2}{5} x 100 = 40%. (c)

(10) Given, cost price of sewing machine = Rs 2000.

     Loss Percentage = 40%

     Selling Price = C.P. - LOSS PERCENTAGE X C.P.

                           = 2000 - 40% OF 2000

                           = 2000 - 800 = 1200.(A)

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