Math, asked by HarshShaw, 1 year ago

log10(xy)=2,log10(x/y)+2log102=2

Answers

Answered by DhruvSarkar223
11
log10(xy) = log10(x/y) + 2log102
or, log10(xy) = log10(x/y) + log(102)^2
or, log10(xy) = log10(x/y x (102)^2)
or, xy = ((102)^2). x)/y
or, y = ((102)^2)/y  (eliminating x on both sides)
or, y^2 = (102)^2
or, y = 102
now, log10(xy) = 2
or, xy = 100
or x = 50/51

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