Question

log2(1-cos(x))-2log2sin(x)+log2(1+cos(x))

Answer 1

Step-by-step explanation:

log2sinx - [log2cosx + log2(1 - tan2x)] = -1

Apply the properties of logs in the bracketed terms first.

log2sinx - log2(cosx(1 - tan2x)) =-1

log2[sinx / (cosx(1 - tan2x))] = -1

The solution to a logarithm is the exponent to a log's base.

2-1 = sinx / [cosx(1 - tan2x)

Then notice that sin(x)/cos(x) is tan(x).

1/2 = tanx / (1 - tan2x)