Question

log2(2 root17-2x))=1-log1/2

Answer 1

Answer:

.

logmn= logm+long

log

Answer 2

Answer:

Step-by-step explanation:

Answer :

x = 4

Solution :

log2(217−−√−2x)=1+log2(x−1)

orlog2(217−2x−−−−−−√x−1)=1

or(217−2x−−−−−−√x−1)=2

or217−2x−−−−−−√=2(x−1)

orx22x+1=17−2x

x2=16

⇒x=4(as x≠−4)