Question

log2* + log27 base 3 = 0​

Answer 1

Answer:

The value of x in above question is 0.25

Answer 2

Answer: $x= \frac{-3}{log(2)}$

Step-by-step explanation:

$log(2^x) + log_{3}27 = 0$

= $log(2^x) + \frac{ log_{e}27}{ log_{e}3} = 0$

= $log(2^x) + \frac{ log_{e}3^3}{ log_{e}3} = 0$

= $x.log(2) + \frac{ 3.log_{e}3}{ log_{e}3} = 0$

= $x.log(2) + 3 = 0$

= $x= \frac{-3}{log(2)}$