Question

log2(x+y) = log3(x-y) = log25/log0.2 Find x and y.

Answer 1

Given that log2(x+y) = log3(x-y) = log25/log0.2

log25/log0.2 
= log25/log (1/5)
= log25/(- log 5)
= - log5 25
= -2  

$log_2(x+y) = -2\\ \\ \Rightarrow x+y = 2^{-2}\\ \\ \Rightarrow x+y = 1/4$

$log3(x-y) = -2\\\\ \Rightarrow x-y = 3^{-2}\\\\ \Rightarrow x-y = 1/9$

$Adding\ them,\\ \\2x = \frac{1}{4} + \frac{1}{9} \\ \\ \Rightarrow 2x = \frac{9+4}{36} = \frac{13}{36} \\ \\ \Rightarrow x = \frac{13}{72}$

$y = \frac{1}{4} - \frac{13}{72} = \frac{18-13}{72} = \frac{5}{72}$

Answer 2

Answer:

i have found this from google

as i am in 8th only.