log2(x2−6x)=3+log2(1−x)
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Step-by-step explanation:
=>log(x²-6x)base2 = 3log2base2 + log(1-x)base2
=>log(x²-6x) = log8+log(1-x)
=>log(x²-6x)=log(8-8x)
=>x²-6x=8-8x
=>x²+2x-8=0
=>x²-2x+4x-8=0
=>(x+4)(x-2)=0
=>x=2,-4
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