Question

(Log2base3)(log3base4)(log4base5)...(log7base8)

Answer 1

Answer:

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Step-by-step explanation:

ANSWER ::

We know that log x base y = log x / log y

Now

(Log2base3)(log3base4)(log4base5)...(log7base8)

= (log2 / log3) × (log3 / log4 ) × (log4 / log5 ) ×....... × (log7 / log8)

= log2 / log8

= log2 / log (2^3)

= log2 / 3log2

= 1/3