Question

Log33/18+log4/7-log22/21=0

Answer 1

Step-by-step explanation:

$log \frac{33}{18} + log \frac{4}{7} - log \frac{22}{21} = 0 \\ \\ LHS = log \frac{33}{18} + log \frac{4}{7} - log \frac{22}{21} \\ \\ = log (\frac{33}{18} \times \frac{4}{7}) - log \frac{22}{21} \\ \\ = log \frac{(\frac{33}{18} \times \frac{4}{7})}{ \frac{22}{21} } \\ \\ = log(\frac{33}{18} \times \frac{4}{7}\times \frac{21}{22} ) \\ \\ = log(\frac{2772}{2772}) \\ \\ = log \: 1 \\ \\ = 0 \\ \\ = RHS \\ \\ thus \: proved$

Answer 2

Answer:

this is ur answer......