Question

Log36/25+log5/4-log9/5

Answer 1

Explanation:

1. Log36/25+log5/4-log9/5

Answer 2

Using the following laws:

a) $log\frac{a}{b} = log(a)+log(b)$

b) $log(ab)=log(a)+log(b)$

c) $log(a^{b})=blog(a)$

$log\frac{36}{5}+log\frac{5}{4}-log\frac{9}{5} \\=log(36)-log(5)+log(5)-log(4)-log(9)+log(5)\\=log(6^{2})-log(2^{2})-log(3^{2})+log(5)\\ =2log(6)-2log(2)-2log(3)+0.7\\=2{log(2X3)}-2X0.3-2X0.47+0.7\\=2log(2)+2log(3)-0.6-0.94+0.7\\=2X0.3+2X0.47-0.6-0.94+0.7\\=0.6+0.94-0.6-0.94+0.7\\=0.7$

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