Question

log5 3 * log3 4 * log2 5 =​

Answer 1

Answer:

(Loga b) = (log b)/(log a)

log ab = b log a

Calculation:

(log3 4) (log4 5) (log5 6) (log6 7) (log7 8) (log8 9)

⇒ (log 4 / log 3) × (log 5 / log 4) × (log 6 / log 5) × (log 7 / log 6) × (log 8 / log 7) × (log 9 / log 8)

⇒ (log 9 / log 3) (∵ Except log 9 and log 3 other terms cancelled out)

We can say log 9 = log10 9

So, log 9 = log 32 = 2 log 3

∴ (log 9 / log 3) = 2 log 3/log 3 =