Question

log8/log2 x log3/log square root 3 = 2 log x

Answer 1

$\frac{log(8)}{log(2)}$*$\frac{log(3)}{log( \sqrt{3})}$ = 2*log(x)
3*$\frac{log(2)}{log(2)}$*2*$\frac{log( \sqrt{3}) }{log( \sqrt{3}) }$ = 2*log(x)
3 = log(x)
x = anti log(3)

Answer 2

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