Math, asked by vinnysiby, 1 month ago

logarithmic differentiation of y=x^sinx + sin^x. please answer it

y=x^sinx + sin^x

Answers

Answered by lusor

2

Answer:

logarithmic differentiation of y=x^sinx + sin^x. please answer it

y=x^sinx + sin^x

Step-by-step explanation:

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