Question

logarithms...plzz ans....thnk u

Answer 1

Hi friend,

log m²n = log m² + log n (as log ab=loga+logb)

log m²n = 2 log m + log n (as logaⁿ = n log a)

Given,

log m = x+y

log n = x-y

Substitute in above

log m²n = 2(x+y) + (x-y)

log m²n = 2x+2y+x-y

log m²n = 3x+y

Answer is 3x+y

Hope it helps

Answer 2

Hey there !!

logm²n can be written as logm²+logn    ( As logab=loga+logb) and logm² can be written as 2logm as logaˣ=xloga

So logm²n=2logm+logn

 But logm=x+y , logn=x-y

logm²n=2(x+y)+x-y

           =2x+2y+x-y

    logm²n =3x+y

HOPE THIS HELPED YOU!!!!