Question

logbx = 2 – a + logb solve this equation by the method of logarithm 

Answer 1

log bx=2-a+log b
log bx-log b=2-a
log(bx/b)=2-a
log x=2-a
log x may be log x to the base e or 10
therefore,x=(2-a)^1/e or (2-a)^1/10

Answer 2

$log_{10} bx=2-a+log_{10} b \\ log_{10}bx-log_{10}b=2-a \\ log_{10} x=2-a \\ x=10^{2-a}$