Question

loge x + log(1+x) = 0 is equivalent to​

Answer 1

Answer:

( - 1 + √5) / 2 ≈ 0.618

Step-by-step explanation:

log x + log (1 + x) = 0

log x = - log (1 + x)

log x = log $(1+x)^{-1}$

x = $(1+x)^{-1}$

x = $\frac{1}{1 + x}$

x(1 + x) = 1

x² + x - 1 = 0

$x_{1}$ = ( - 1 + √5) / 2

$x_{2}$ = ( - 1 - √5) / 2 N/A

x = ( - 1 + √5) / 2 ≈ 0.618

Answer 2

Answer:

x²+x-1=0

Step-by-step explanation:

logx+log(1+x)=0

=>logx= —log(1+x)

=>logx=log(1+x)-¹

=>x=1/1+x

=>x²+x= —1

=>x²+x—1=0 (Ans)