Question

logs (2x) + logs(x-4) = logs 24​

Answer 1

Step-by-step explanation:

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Answer 2

Answer :

x = 6

Solution :

• Given : log2x + log(x - 4) = log24
• To find : x = ?

We have ,

=> log2x + log(x - 4) = log24

=> log2x(x - 4) = log24

=> 2x(x - 4) = 24

=> x(x - 4) = 24/2

=> x² - 4x = 12

=> x² - 4x - 12 = 0

=> x² - 6x + 2x - 12 = 0

=> x(x - 6) + 2(x - 6) = 0

=> (x - 6)(x + 2) = 0

=> x = 6 , -2

=> x = 6 (appropriate value)

Note : x = -2 is rejected value . Because if x = -2 then , log2x = log2(-2) = log(-4) and log(x - 4) = log(-2 - 4) = log(-6) and we know that log(-ve) is not defined .

Hence x = 6 .