Question

logtan5+logtan25+logtan65+logtan85​

Answer 1

Answer:

>>>>log( tan5) + log( tan25) + Iog( tan65) + log( tan85)

>>>>[ use, logm + logn = logmn ]

Step-by-step explanation:

HENCE,

>>>>log{ tan5 .tan25 . tan65° . tan85° }

>>>>log{ tan( 90-85) .tan(90-65).tan65.tan85}

>>>>log{ cot85. cot65°.tan65°.tan85°}

>>>>log{ ( tan85°.cot85°).( tan65°.cot65°)}

>>>>log{ 1 × 1 } = log(1 )

>>>>0

I HOPE IT HELPS.