Question

logx^2.y^2 base z^2. Simplify it

Answer 1

hello users

solution:-
we know that
$log_{b}a = \frac{log a}{logb}$
And
$logm^{n} = n log m$
And
$log mn = log m + log n$

Here,

$log_{ z^{2} } x^{2} y^{2}$

= $\frac{log x^{2} y^{2} }{log z ^{2} }$

=$\frac{[ log x^{2} + log y^{2} ] }{log z^{2} }$

= $\frac{[ 2log x + 2 log y ] }{2 log z }$

=$\frac{2[log x + log y ] }{2 log z }$

=$\frac{log x + log y }{ log z }$

Hence
'D' is the correct option

@ hope it helps :)