logx^3/3 base 3 - 2log3x^3 base 3 = a - blogx base 3 then a+b =?
Please solve it quickly....
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Step-by-step explanation:
logx^3/3 to base 3-log9x^6
log(x^3/3)/9x^6 to base 3
log1/27x^3 to base 3
-3log3 to base 3-3logx to base3
-3-3logx=a-blogx
compare
a=-3,b=3
a+b=-3+3=0
option 3
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