Question

logx =-3.7781then log(x power 5) =

Answer 1

Hey there!

If the given exponential form is a^n = b then logarithmic form is
$log_{a}(b) = n$

We know that,
$log( {m}^{n} ) = n log(m)$


Given,

log x = -3. 7781

We are asked to find,

$log( {x}^{5} ) \\ \\ = 5 log(x) \\ \\ = 5 \times - 3.7781 \\ \\ = - 18.8905$

Hope helped!

Answer 2

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