Question

[Logx(3).logx(4).logx(5)]= [logx(3).logx(4)] + [logx(3).logx(4)] + [logx(5).logx(4)]

Answer 1

 answer

x=1, 10√3,10−√3. Explanation: log (x3)=3logx. 3logx=(logx)3 (logx)3−3logx=0. logx((logx )2−3) =0. logx=0, (logx)2−3=0. log x=0 means x=1 ..