Question

logx 4+logx16+logx64=12​

Answer 1

Answer:

Step-by-step explanation:

logx4+logx16+logx64=12  

=>logx(4*16*64)=12  

=>logx(2^2 * 2^4 * 2^6)=12  

=>logx(2^12)=12  

=>x^12=2^12  

=>x=2