Math, asked by sonunag1, 1 year ago

logx+log x^2 +log x^3.......log x^n value is

Answers

Answered by Kkashyap
2
Hey there,

log x+log x^2+log x^3 +...+log x^n

=>log (x×x^2×x^3×..×x^n)

=>log x^{n(n+1)/2}. ( Sum of first n terms =n(n+1)/2 )

=>n(n+1)/2 log x. ( Using log a^b=b log a)

Hope it helps

sonunag1: thanks
Powerman123: hahahah
Kkashyap: Thanks dear for branliest
Powerman123: hi
Answered by Powerman123
0
AS, log a^b = b×log a

SO, log x^n = n×log x

ANSWER IS = n×log x

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