logx+log x^2 +log x^3.......log x^n value is
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Hey there,
log x+log x^2+log x^3 +...+log x^n
=>log (x×x^2×x^3×..×x^n)
=>log x^{n(n+1)/2}. ( Sum of first n terms =n(n+1)/2 )
=>n(n+1)/2 log x. ( Using log a^b=b log a)
Hope it helps
log x+log x^2+log x^3 +...+log x^n
=>log (x×x^2×x^3×..×x^n)
=>log x^{n(n+1)/2}. ( Sum of first n terms =n(n+1)/2 )
=>n(n+1)/2 log x. ( Using log a^b=b log a)
Hope it helps
sonunag1:
thanks
Answered by
0
AS, log a^b = b×log a
SO, log x^n = n×log x
ANSWER IS = n×log x
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×-×-×-×-×-×-×-×-×-×-×-×-×-×-×-×-×-×
SO, log x^n = n×log x
ANSWER IS = n×log x
GIVE THUMBS UP
MARK AS BRAINLIEST ANSWER
×-×-×-×-×-×-×-×-×-×-×-×-×-×-×-×-×-×
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