Math, asked by sangithakumar24, 19 days ago

logx + [ log ( xy^8 )/ (log x)^2 + (log y) ^2 ] = 2. logy + [ log ( x^8/y )/ (log x)^2 + (log y) ^2 ] = 0 find value of x and y

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Answered by hareramu20

0

dt8ins3800oncsee588 ģğhñ

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